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How is the following equation possible?

\[ x^3 - 6x - 40 = (x-4)(x^2+4x+10) \]

I forgot

Note by Jason Chrysoprase 2 years ago

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*italics*

_italics_

**bold**

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1. numbered2. list

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paragraph 2

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> This is a quote

This is a quote

# I indented these lines # 4 spaces, and now they show # up as a code block. print "hello world"

2 \times 3

2^{34}

a_{i-1}

\frac{2}{3}

\sqrt{2}

\sum_{i=1}^3

\sin \theta

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\(x^3-6x-40 \\ = x^3-4x^2+4x^2-16x+10x-40 \\ = x^2(x-4)+4x(x-4)+10(x-4) \\ = (x-4)(x^2+4x+10)\)

Its not something to memorize to forget though :P

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Thanks Nihar, it was quite helpful.

\( x^3 - 6x - 40 \\ = x^3 \color{red}{- 4x^2 + 4x^2 - 16x + 10x} - 40 \)

How did you get those red numbers ?

So that we can factor out \((x-4)\) from each pair.

@Nihar Mahajan – thx mate

I'm felling silly now XD

I'm 13

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Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

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TopNewest\(x^3-6x-40 \\ = x^3-4x^2+4x^2-16x+10x-40 \\ = x^2(x-4)+4x(x-4)+10(x-4) \\ = (x-4)(x^2+4x+10)\)

Its not something to memorize to forget though :P

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Thanks Nihar, it was quite helpful.

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\( x^3 - 6x - 40 \\ = x^3 \color{red}{- 4x^2 + 4x^2 - 16x + 10x} - 40 \)

How did you get those red numbers ?

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So that we can factor out \((x-4)\) from each pair.

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I'm felling silly now XD

I'm 13

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