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Help For Integration

\[ \large \int \tan^{-1} x \cdot \ln(1+x^2) \, dx = \, ? \]

Clarification: \(\tan ^{ -1 }{ \left( x \right) } =\text{arctan}(x)\).

Note by Rishabh Deep Singh
8 months, 1 week ago

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Substitute \(\arctan(x) = y\), then use Integration by parts. Harsh Shrivastava · 8 months, 1 week ago

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