Help in Bitwise and Operator

Find all natural numbers nn that satisfy condition n&x = n ? Where x is a Any constant Positive Integer.

Note by Rishabh Deep Singh
1 year, 9 months ago

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Sir are you CSE IITKGP?

Ayaen Shukla - 1 year, 6 months ago

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I am a Mechanical Student At IIT Kharagpur.

Rishabh Deep Singh - 1 year, 6 months ago

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Okay! I am CSE at IIT Patna.

Ayaen Shukla - 1 year, 6 months ago

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@Ayaen Shukla pm me on facebook

Rishabh Deep Singh - 1 year, 6 months ago

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@Agnishom Chattopadhyay @Chew-Seong Cheong

Rishabh Deep Singh - 1 year, 9 months ago

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I Found a Blog about it on Codeforces as SOS Dynamic Programming @Agnishom Chattopadhyay

Rishabh Deep Singh - 1 year, 7 months ago

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That's cool. Send me the link.

Agnishom Chattopadhyay Staff - 1 year, 7 months ago

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By next number, do you mean keeping x fixed, you want to search for the next such n?

Agnishom Chattopadhyay Staff - 1 year, 9 months ago

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I have edited the Problem a little bit.

Rishabh Deep Singh - 1 year, 9 months ago

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@Rishabh Deep Singh Well, for the bits where x has a 1, n can have anything, and for the places where x has a 0, n must have a 0 too. Does that answer your question?

Agnishom Chattopadhyay Staff - 1 year, 9 months ago

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@Agnishom Chattopadhyay Can u write code for that ? to print all numbers Please?

Rishabh Deep Singh - 1 year, 9 months ago

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@Rishabh Deep Singh That's an interesting exercise. If you are stuck on this, I'd urge you to consider writing your code recursively. That might help. Or if you are not concerned about efficiency, you may loop over all the values and check if it satisfies the condition.

Agnishom Chattopadhyay Staff - 1 year, 9 months ago

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@Agnishom Chattopadhyay Efficiency is More important, Can u help me with code?

Rishabh Deep Singh - 1 year, 9 months ago

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