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# Help me

From a disc of mass 2kg and radius 4m a small disc of radius 1m with center $$O^{\prime}$$ is extracted .The new moment of inertia about an axis passing through O perpendicular to plane of disc is

Note by Kyle Finch
2 years, 3 months ago

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The answer is 247/16 kgm^2 · 2 years, 3 months ago

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Moment of Inertia of Initial disc about center = Moment of inertia about center of part that is removed+ moment of inertia about center of whatever is left · 2 years, 3 months ago

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I missed the diagram. Plz see above · 2 years, 3 months ago

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I'm still not getting a diagram · 2 years, 3 months ago

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Now u may see · 2 years, 3 months ago

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What I said above still applies. The MOI of the whole disc is sum of the removed part and what's left. · 2 years, 3 months ago

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OK thanks , can u also tell me the solution to this $$\frac{dy}{dx}=\frac{x+\sqrt{x^2-4y}}{2}$$ · 2 years, 3 months ago

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