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# Help me

From a disc of mass 2kg and radius 4m a small disc of radius 1m with center $$O^{\prime}$$ is extracted .The new moment of inertia about an axis passing through O perpendicular to plane of disc is

Note by Kyle Finch
1 year, 6 months ago

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The answer is 247/16 kgm^2 · 1 year, 6 months ago

Moment of Inertia of Initial disc about center = Moment of inertia about center of part that is removed+ moment of inertia about center of whatever is left · 1 year, 6 months ago

I missed the diagram. Plz see above · 1 year, 6 months ago

I'm still not getting a diagram · 1 year, 6 months ago

Now u may see · 1 year, 6 months ago

What I said above still applies. The MOI of the whole disc is sum of the removed part and what's left. · 1 year, 6 months ago

OK thanks , can u also tell me the solution to this $$\frac{dy}{dx}=\frac{x+\sqrt{x^2-4y}}{2}$$ · 1 year, 6 months ago