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From a disc of mass 2kg and radius 4m a small disc of radius 1m with center \(O^{\prime}\) is extracted .The new moment of inertia about an axis passing through O perpendicular to plane of disc is

Note by Kyle Finch
2 years, 1 month ago

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The answer is 247/16 kgm^2 Kyle Finch · 2 years, 1 month ago

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Moment of Inertia of Initial disc about center = Moment of inertia about center of part that is removed+ moment of inertia about center of whatever is left Raghav Vaidyanathan · 2 years, 1 month ago

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@Raghav Vaidyanathan I missed the diagram. Plz see above Kyle Finch · 2 years, 1 month ago

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@Kyle Finch I'm still not getting a diagram Raghav Vaidyanathan · 2 years, 1 month ago

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@Raghav Vaidyanathan Now u may see Kyle Finch · 2 years, 1 month ago

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@Kyle Finch What I said above still applies. The MOI of the whole disc is sum of the removed part and what's left. Raghav Vaidyanathan · 2 years, 1 month ago

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@Raghav Vaidyanathan OK thanks , can u also tell me the solution to this \(\frac{dy}{dx}=\frac{x+\sqrt{x^2-4y}}{2}\) Kyle Finch · 2 years, 1 month ago

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