From a disc of mass 2kg and radius 4m a small disc of radius 1m with center $O^{\prime}$ is extracted .The new moment of inertia about an axis passing through O perpendicular to plane of disc is

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Moment of Inertia of Initial disc about center = Moment of inertia about center of part that is removed+ moment of inertia about center of whatever is left

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TopNewest@Raghav Vaidyanathan @Ronak Agarwal @Jake Lai

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Moment of Inertia of Initial disc about center = Moment of inertia about center of part that is removed+ moment of inertia about center of whatever is left

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I missed the diagram. Plz see above

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I'm still not getting a diagram

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$\frac{dy}{dx}=\frac{x+\sqrt{x^2-4y}}{2}$

OK thanks , can u also tell me the solution to thisLog in to reply

The answer is 247/16 kgm^2

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