From a disc of mass 2kg and radius 4m a small disc of radius 1m with center \(O^{\prime}\) is extracted .The new moment of inertia about an axis passing through O perpendicular to plane of disc is

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TopNewestThe answer is 247/16 kgm^2 – Kyle Finch · 2 years, 3 months ago

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Moment of Inertia of Initial disc about center = Moment of inertia about center of part that is removed+ moment of inertia about center of whatever is left – Raghav Vaidyanathan · 2 years, 3 months ago

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– Kyle Finch · 2 years, 3 months ago

I missed the diagram. Plz see aboveLog in to reply

– Raghav Vaidyanathan · 2 years, 3 months ago

I'm still not getting a diagramLog in to reply

– Kyle Finch · 2 years, 3 months ago

Now u may seeLog in to reply

– Raghav Vaidyanathan · 2 years, 3 months ago

What I said above still applies. The MOI of the whole disc is sum of the removed part and what's left.Log in to reply

– Kyle Finch · 2 years, 3 months ago

OK thanks , can u also tell me the solution to this \(\frac{dy}{dx}=\frac{x+\sqrt{x^2-4y}}{2}\)Log in to reply

@Raghav Vaidyanathan @Ronak Agarwal @Jake Lai – Kyle Finch · 2 years, 3 months ago

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