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From a disc of mass 2kg and radius 4m a small disc of radius 1m with center $O^{\prime}$ is extracted .The new moment of inertia about an axis passing through O perpendicular to plane of disc is

Note by Kyle Finch
5 years, 6 months ago

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- 5 years, 6 months ago

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Moment of Inertia of Initial disc about center = Moment of inertia about center of part that is removed+ moment of inertia about center of whatever is left

- 5 years, 6 months ago

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I missed the diagram. Plz see above

- 5 years, 6 months ago

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I'm still not getting a diagram

- 5 years, 6 months ago

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Now u may see

- 5 years, 6 months ago

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What I said above still applies. The MOI of the whole disc is sum of the removed part and what's left.

- 5 years, 6 months ago

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OK thanks , can u also tell me the solution to this $\frac{dy}{dx}=\frac{x+\sqrt{x^2-4y}}{2}$

- 5 years, 6 months ago

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The answer is 247/16 kgm^2

- 5 years, 6 months ago

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