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Find the minimum value of expression \(6\sin x - 8\cos x\)

Help please!

Note by Nitesh Chaudhary
2 years, 1 month ago

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the answer is -10 as the minimum value of the expression Asinx + Bcosx +C = 0 is C - (A^2 + B^2)^1/2

Anurag Patnaikuni - 2 years, 1 month ago

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A very very easy question. The answer is \(-\sqrt{6^2 + {(-8)}^2} = -\sqrt{100} = -10\). @Nitesh Chaudhary lets just forget our disputes and be friends. Youe choice now.

Ashish Siva - 1 year, 5 months ago

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Is the answer -10?

Harsh Shrivastava - 2 years, 1 month ago

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Yes it is , can you post the method plzz

Nitesh Chaudhary - 2 years, 1 month ago

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This may help you

Harsh Shrivastava - 2 years, 1 month ago

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@Harsh Shrivastava Thanks , got it :)

Nitesh Chaudhary - 2 years, 1 month ago

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@Nitesh Chaudhary No prob.

Harsh Shrivastava - 2 years, 1 month ago

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Sir @Mehul Arora Sir @Calvin Lin @Pi Han Goh @Harsh Shrivastava

Nitesh Chaudhary - 2 years, 1 month ago

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Thanks for mentioning me man. I think that you've got your answer, but still

\(min(asin(x)+bcos(x)+c=0)= c- \sqrt {a^2+b^2}\)

Mehul Arora - 2 years, 1 month ago

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