Hey guys,

Today I came across a question about the function \(f(x)\), which takes the value \(x\) when \(x \in Q\) and the value \(1-x\) when \(x \notin Q\). Is this function continuous at any point?

I thought that \(f(x)\) would be continuous at \(x=0.5\) since the left and right hand limits seem to approach \(0.5\) near \(x=0.5\).

Am I correct? If so, why? If not, why?

Thanks!

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## Comments

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TopNewestDo you know what is the delta epsilon definition of a limit?

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Thanks a lot! I went through the wiki and worked out the answer to my question. The epsilon-delta definition is broader than the one I learnt in school...

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hi

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Hey.

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How are you

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These are called drichlet functions and these are continuos when both equations are equal

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