Plz i request u to post a solution for this as I don't know the correct answer

A bag contains **3 maths books** and **2 physics books**. A book is drawn at random, if it is of maths, **2 more books of maths together** with this book put back in the bag and if it is of physics it is not replaced in the bag.This experiment is **repeated 3 times**.If **third draw gives maths book**,what is the **probability** that **first two drawn books were of physics**.

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## Comments

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TopNewestIs the answer 42/347?

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i guess it should be \(\frac{42}{357}\) which is equal to \(\frac{2}{17}\)

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i don't know the answer @Rajorshi Chaudhuri .. can u post ur method in brief

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I solved it as: Let math book be M and physics book be P. So the last book is M and it can be with MMM, MPM, PMM, PPM. Now, P(MMM)=(3/5)

(5/7)(7/9)=1/3. Similarly for the rest. And out of this we need PPM.Log in to reply

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We have to use Bayes theorem right ? Calculate probability for the four events separately like MMM , MPM , etc. It will be a messy answer

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ya u r correct,its a question from one of my friends quiz test paper

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