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Help needed

Kindly help in the following question. give rough idea.

Note by Mahimn Bhatt
2 years, 8 months ago

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1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

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Substitute \(x^2=9a^2-y^2\) in the equation of ellipse and make \(D>0\)

Pranjal Jain - 2 years, 8 months ago

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It does not contain any term in \(\large{y}\) , just \(\large{y^{2}} \) and some terms in \(\large{c}\) and \(\large{a}\)

Mahimn Bhatt - 2 years, 8 months ago

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\(\dfrac{9a^2-y^2}{4c^2}+\dfrac{y^2}{c^2}=1\\\Rightarrow 9a^2-y^2+4y^2=4c^2\\\Rightarrow 3y^2=4c^2-9a^2>0\\\Rightarrow 4c^2>9a^2\)

Pranjal Jain - 2 years, 8 months ago

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@Pranjal Jain Using this inequality, check out which option satisfies.

Pranjal Jain - 2 years, 8 months ago

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@Pranjal Jain yes i m stuck now...

Mahimn Bhatt - 2 years, 8 months ago

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