If \(a, b, c, d\in\mathbb{R}\) such that

\[|a-b|+|c-d|=99\]

\[|a-c|+|b-d|=1\]

then the possible value(s) of \(|a-d|+|b-c|\) are.....

If \(a, b, c, d\in\mathbb{R}\) such that

\[|a-b|+|c-d|=99\]

\[|a-c|+|b-d|=1\]

then the possible value(s) of \(|a-d|+|b-c|\) are.....

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TopNewesthappy bday – Rajat Kharbanda · 2 years, 8 months ago

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– Aneesh Kundu · 2 years, 8 months ago

Thnx a lot. Actually it was yesterday.Log in to reply

consider a>b>c>d, then plug in to open mod. then solve by cases. ans is 1,98,99,100. – Rajat Kharbanda · 2 years, 8 months ago

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I coudn't go any further. I have not verified the equality cases either. – Aneesh Kundu · 2 years, 8 months ago

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Cases is not really a gud option (24 cases is just tooooo much). – Aneesh Kundu · 2 years, 8 months ago

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– Rajat Kharbanda · 2 years, 8 months ago

where did you get the question from . actually you need not solve 24 cases.most of them are sameLog in to reply

– Aneesh Kundu · 2 years, 8 months ago

Oh... That sounds great I'll try that. My teacher gave me this one.Log in to reply

Is the answer 98,99,100??? – Abhineet Nayyar · 2 years, 8 months ago

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Can u state an example for each of the values? It would be really helpful. – Aneesh Kundu · 2 years, 8 months ago

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