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If $a>b>c>d$ then we can remove the modulus from both the equations. Rearranging the last equation we get our expression, but that would give us the value to be 1.

Cases is not really a gud option (24 cases is just tooooo much).

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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

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## Comments

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TopNewesthappy bday

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Thnx a lot. Actually it was yesterday.

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consider a>b>c>d, then plug in to open mod. then solve by cases. ans is 1,98,99,100.

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I was able to prove that $0\leq |a-d|+|b-c|\leq 100$

I coudn't go any further. I have not verified the equality cases either.

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If $a>b>c>d$ then we can remove the modulus from both the equations. Rearranging the last equation we get our expression, but that would give us the value to be 1.

Cases is not really a gud option (24 cases is just tooooo much).

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where did you get the question from . actually you need not solve 24 cases.most of them are same

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Is the answer 98,99,100???

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Don't know that.

Can u state an example for each of the values? It would be really helpful.

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@Calvin Lin @Sudeep Salgia @Sandeep Bhardwaj @megh choksi @Arron Kau @Christopher Boo @Dinesh Chavan @Jon Haussmann @Michael Mendrin @Pi Han Goh @Chew-Seong Cheong @Alan Enrique Ontiveros Salazar @Steven Zheng @Joel Tan @Krishna Sharma @Sreejato Bhattacharya

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