# Help needed in an MCQ

$\large \displaystyle I_n \int_{\pi}^\pi \frac1{1 + 2^{\sin(x/2)} } \left( \frac{\sin(nx/2)}{\sin(x/2)} \right)^2 \, dx$

Hi brilliant! I've a doubt in calculus! The question is above.

The options are:

A) $${ I }_{ n }={ I }_{ n+1 }\forall n\ge 1$$

B) $${ I }_{ 0 },{ I }_{ 1 },{ I }_{ 2 },{ ...,I }_{ n }\quad are\quad in\quad AP$$

C) $$\sum _{ m=0 }^{ 9 }{ { I }_{ 2m }=90\pi }$$

D) $$\sum _{ m=0 }^{ 10 }{ { I }_{ m }=55\pi }$$

More than one options are right

• Please provide detail solutions!

• Please don't fluke answers.

Note by Aditya Kumar
2 years, 10 months ago

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## Comments

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Top Newest

First substitute x by -x and add to get rid of the denominator. Then use the steps in the solution of this problem. This should help you.

- 2 years, 10 months ago

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i think you have written the statement wrong it should be -pi to pi , correct it then only answers can be given @Aditya Kumar if it's -pi to pi then the answer would be B,C,D .....just correct it !

- 1 year, 9 months ago

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First substitute x by -x and add to get rid of the denominator.And then evaluate $$I_0$$,$$I_1$$,$$I_2$$.... which will come out to be $$0,\pi ,2\pi.....$$ hence they will be in AP .So B,C,D.

And that problem by Sudeep can also be evaluated like that.

- 2 years, 10 months ago

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Ooh nice :)

- 2 years, 10 months ago

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- 2 years, 10 months ago

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I'm sure that it's one of a, b, c or d.

- 2 years, 10 months ago

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Thanks for enlightening!

- 2 years, 10 months ago

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There is no one :(

- 2 years, 10 months ago

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What????

- 2 years, 10 months ago

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