Hello everyone,

I don't know if the following generalization exists, but I want to give it a go. If you want to join, please do and help me. For this mini research to be a success, you need to help me with this problem. I found this to be little tricky and confusing stuff. Here it is.

Here is a regular pentagon named \(ABCDE\). Suppose, equal charges \(q\) are placed on each of its vertex.Now here's the calculation I need from your side. Find the magnitude of the net force exerted on a charge by the other \(4\) charges.

Details and Assumptions:

The length of each side of the pentagon is assumed to be \(a\).

Assume the medium to be vacuum.

Thanks \(!\)

*Swapnil Das*

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestfirst find the distance between the test charge and 4 other charges. it is = a for 2 charge

first we find force due to them just write a vector and we find that one component of both is canceling

net ={2sin(36)kq^2}/(a^(2))

other which are at distance=2asin(54)

net due to them=(cos(18)/sin^2{54}){kq^2}/(2a^(2))

total={2sin(36)kq^2}/(a^(2))+(cos(18)/sin^2{54}){kq^2}/(2a^(2))

Log in to reply

Nice!! There can be a shorter way, I suppose

Log in to reply