When we suck water from straw first we basically decrease the pressure inside the straw but the pressure outside the straw remains \(1atm\). So water rises inside the straw up to the level to equate the pressure inside and outside the straw. As the pressure outside the straw is \(1atm\) and the pressure inside the straw is \(hdg\) where \(h\) is the height of water inside the straw. So \( 1 atm=hdg\). Just find \(h\)(be careful with the units).:)

By sucking the water we are decrease the randomness of the molecules ( as it will get more time to oscillate between 2 points), now as you said , for achieving the equilibrium state water rises.

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TopNewestWhen we suck water from straw first we basically decrease the pressure inside the straw but the pressure outside the straw remains \(1atm\). So water rises inside the straw up to the level to equate the pressure inside and outside the straw. As the pressure outside the straw is \(1atm\) and the pressure inside the straw is \(hdg\) where \(h\) is the height of water inside the straw. So \( 1 atm=hdg\). Just find \(h\)(be careful with the units).:)

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Nice explanation , i too understood it

Another but same -

By sucking the water we are decrease the randomness of the molecules ( as it will get more time to oscillate between 2 points), now as you said , for achieving the equilibrium state water rises.

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Thanks! :)

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Which of the solutions did you have trouble understanding?

Once you clarified your doubts, can you help others out by writing a solution that they can understand easily? Thanks!

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@Deepanshu Gupta @Ronak Agarwal @Mvs Saketh @Karthik Kannan @Sudeep Salgia @jatin yadav @Krishna Sharma @satvik pandey

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Its like a barometer with water instead of mercury :)

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