Help please

cos5x+cos4x12cos3x\huge\int \dfrac{\cos^5 x+\cos^4 x}{1-2\cos 3x}

Note by Rohit Ner
3 years, 11 months ago

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I am getting a nice closed form if the numerator is cos5x+cos4x \cos 5x + \cos 4x . I think if it is a JEE problem then the numerator should be what I have written. Can you please check? Otherwise I'll try with this again.

Sudeep Salgia - 3 years, 11 months ago

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I am sure about the question. The reason I put the jee tag was to get to know if there are any methods of jee applicable.

Rohit Ner - 3 years, 11 months ago

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What makes you think that it has a closed form?

Pi Han Goh - 3 years, 11 months ago

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This problem was given to me by my class mate. I tried every integration technique possible. Even I doubt if there exists a valid closed form for it. Please help me sir.

Rohit Ner - 3 years, 11 months ago

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There's no simple closed form without using hypergeometric functions. Apply cos(3x)/cos(2x)=12cos(2x) \cos(3x) /\cos(2x) = 1 - 2\cos(2x) and reducing the powers of trigonometric functions to 1 shows that we are essentially solving for at least one of sin(ax)csc(bx)dx \int \sin(ax) \csc(bx) dx , sin(ax)sec(bx)dx \int \sin(ax) \sec(bx) dx , cos(ax)sec(bx)dx\int \cos(ax) \sec(bx) dx , cos(ax)csc(bx)dx \int \cos(ax) \csc(bx) dx which can't be stated in terms of elementary functions because for all of these cases, b1b \ne 1 .

Pi Han Goh - 3 years, 11 months ago

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I know a method but haven't done it yet.

  1. Write cos5(x)\cos^5(x) and cos4(x)\cos^4(x) as 116(10cos(x)+5cos(3x)+cos(5x))\frac{1}{16}(10 \cos(x) + 5 \cos(3x) + \cos(5x)) and 18(3+4cos(2x)+cos(4x))\frac{1}{8}(3 + 4 \cos(2x) + \cos(4x)).

  2. Substitute z=eixz = {e}^{ix}.

  3. Then, you would get a rational polynomial function in terms of z which can "easily" be solved using Partial Fraction or Division approach.

I know this method is way too tedious but that's the most general way to tackle these types of problems.

Kartik Sharma - 3 years, 11 months ago

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You can't solve it by simple Partial Fractions because the denominator of this function does not have any "nice" roots.

Pi Han Goh - 3 years, 11 months ago

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Oh! I see. I hadn't checked it so I might be wrong. If it doesn't have "nice" roots then also it doesn't matter, computer will do it, it doesn't discriminate b/w real and complex :P

Kartik Sharma - 3 years, 11 months ago

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@Kartik Sharma We might have different opinion of "nice" closed form. Does the integration of 1x3+3x2+5x+7 \frac1{x^3 + 3x^2 + 5x+7} have a nice form?

Pi Han Goh - 3 years, 11 months ago

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@Pi Han Goh That's quite nice! :P For me, everything has a nice "closed"(I didn't use this word originally) form. Even the error function does! :P

Kartik Sharma - 3 years, 11 months ago

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@Kartik Sharma To me, even the error function is not "nice". I only consider elementary functions to be "nice".

If you consider all of these to have a "nice" closed form, then it's hard to judge whether an integral is worth solving or not. Don't you think so?

Pi Han Goh - 3 years, 11 months ago

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I don't think this is an IITJEE question. This question is not integrable to our knowledge(atleast till JEE point of view). You can use higher level integration to solve this.

Harikrishna Nair - 3 years, 9 months ago

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