Hello Brilliantians!

Also suggest any good book or website for studying geometrical optics.

Thanks!

Note by Harsh Shrivastava
2 years, 9 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

For question 11, there is missing information. All the options are possible.

For question 12, no image should be formed.

The second black line is the concave lens.

The red lines, or the rays of light, would diverge upon hitting the concave lens, and the rays would not intersect again. Since in order for another image to be formed after the light hit the concave lens, the 2 rays of light has to intersect, there would be no image formed.

- 2 years, 9 months ago

11th Question's answer is 6 cm.

- 2 years, 8 months ago

- 2 years, 8 months ago

Tomorrow.

- 2 years, 8 months ago

This is quite good, as are most Schaum's problem books:

Staff - 2 years, 9 months ago

Thanks sir!

BTW can you help me with question no. 11 & 12?

- 2 years, 9 months ago

- 2 years, 9 months ago

11:-2.25 ?

- 2 years, 9 months ago

I don't know the answer... Anyways how did you reached till there?

- 2 years, 9 months ago

Oh sorry, I thought it was convex mirror, wrong answer (Seriously sorry).

- 2 years, 9 months ago

I feel that the 11th question is incomplete.

- 2 years, 9 months ago

11- 6cm 12 - shifts away from the lens system

- 2 years, 8 months ago

Hints for 11 which should be enough to solve it.

1. Note that linear magnification of a lens is given by $$\large \frac{v}{u}$$. Linear magnification is length of image divided by length of object.

2. The second crucial thing to note is that focal length remains unchanged in both the cases. Note that $$\large \frac{1}{f} = \frac{1}{v} - \frac{1}{u}$$.

- 2 years, 5 months ago