I need a help in this problem. Please give a hint for question 17. The answer to this problem is 3:5.

Thanks!

I need a help in this problem. Please give a hint for question 17. The answer to this problem is 3:5.

Thanks!

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewestBtw , which book ? @Harsh Shrivastava – Aniket Sanghi · 3 months, 3 weeks ago

Log in to reply

I have seen your name in recent solvers of many hard physics problems.

Please share some tips, thanks!

Also congrats for an amazing air 23 in aiits. – Harsh Shrivastava · 3 months, 3 weeks ago

Log in to reply

Btw can you please tell what sources you use for physics problems? Which books?(not for theory but

goodproblems.)Thanks.

@Aniket Sanghi – Harsh Shrivastava · 3 months, 3 weeks ago

Log in to reply

– Aniket Sanghi · 3 months, 3 weeks ago

Also , remember one thing - ' In Physics any question can be solved , if your concepts are perfect '. So 1st try to perfect your concepts . Try to solve the question more than asked , that is the question may be simple but their may be many things in it to think upon , using which good questions can be framed . :)Log in to reply

– Aniket Sanghi · 3 months, 3 weeks ago

I believe in cengage as 1st priority to gain confidence in basic , medium and some hard problems . Then I complete all q from it ( approx 200 to 300 q per chap) . Then I move to solve harder problems , I solve Irodov , Krotov , Brilliant , and I also try to make tougher questions on a topic which I didn't face in a book so as to check my knowledge and also to gain perfection! . :)Log in to reply

If you see geometry carefully , A0A1:A0A2:A0A3 = 3 : 5 : 6 .

How ? , see this - mark pts. Between A and A1 as B1 (above ) and B2 ( below) , similarly between A1 and A2 as B3 and B4 and between A2 and A3 as B5 and B6.

By geometry , angle A1A0B1= A2A1B3 = A3A2B5 = let x .

A0A1 = 2 × 3lcosx, A1A2 = 2 × 2lcosx, A2A3 = 2 × lcosx. And hence the ratio , A0A1:A0A2:A0A3 = 3 : 5 : 6 .

Differentiating both sides w.r.t t , we get v1 : v2 : v3 = 3 : 5 : 6 – Aniket Sanghi · 3 months, 3 weeks ago

Log in to reply

– Harsh Shrivastava · 3 months, 3 weeks ago

Thank you very much bro!Log in to reply

@Aniket Sanghi @Prakhar Bindal – Harsh Shrivastava · 3 months, 3 weeks ago

Log in to reply

In order to find lengths AOA1 , AOA2 I Used slightly different approach . I firstly used the fact that diagonals of rhombus bisect each other and then the property of parallogram sum of squares of sides = sum of squares of diagonals .

That will yield you same answer @Harsh Shrivastava – Prakhar Bindal · 3 months, 3 weeks ago

Log in to reply

@Prakhar Bindal – Harsh Shrivastava · 3 months, 3 weeks ago

Same questions to you that I have asked aniket, please reply thanksLog in to reply

@Harsh Shrivastava BTW I Did not got 23 in AIITS :p (as you told to look at questions of aniket) – Prakhar Bindal · 3 months, 3 weeks ago

Log in to reply

– Harsh Shrivastava · 3 months, 3 weeks ago

Oh thanks for response.Log in to reply