# Length And Speed Problem

I need a help in this problem. Please give a hint for question 17. The answer to this problem is 3:5.

Thanks!

Note by Harsh Shrivastava
2 years ago

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Btw , which book ? @Harsh Shrivastava

- 2 years ago

Any tips for problem solving in physics?

I have seen your name in recent solvers of many hard physics problems.

Also congrats for an amazing air 23 in aiits.

- 2 years ago

It is from a magazine named "Physics for you".

Btw can you please tell what sources you use for physics problems? Which books?(not for theory but good problems.)

Thanks.

- 2 years ago

Also , remember one thing - ' In Physics any question can be solved , if your concepts are perfect '. So 1st try to perfect your concepts . Try to solve the question more than asked , that is the question may be simple but their may be many things in it to think upon , using which good questions can be framed . :)

- 2 years ago

I believe in cengage as 1st priority to gain confidence in basic , medium and some hard problems . Then I complete all q from it ( approx 200 to 300 q per chap) . Then I move to solve harder problems , I solve Irodov , Krotov , Brilliant , and I also try to make tougher questions on a topic which I didn't face in a book so as to check my knowledge and also to gain perfection! . :)

- 2 years ago

If you see geometry carefully , A0A1:A0A2:A0A3 = 3 : 5 : 6 .

How ? , see this - mark pts. Between A and A1 as B1 (above ) and B2 ( below) , similarly between A1 and A2 as B3 and B4 and between A2 and A3 as B5 and B6.

By geometry , angle A1A0B1= A2A1B3 = A3A2B5 = let x .

A0A1 = 2 × 3lcosx, A1A2 = 2 × 2lcosx, A2A3 = 2 × lcosx. And hence the ratio , A0A1:A0A2:A0A3 = 3 : 5 : 6 .

Differentiating both sides w.r.t t , we get v1 : v2 : v3 = 3 : 5 : 6

- 2 years ago

Thank you very much bro!

- 2 years ago

- 2 years ago

Aniket has done absolutely correct!.

In order to find lengths AOA1 , AOA2 I Used slightly different approach . I firstly used the fact that diagonals of rhombus bisect each other and then the property of parallogram sum of squares of sides = sum of squares of diagonals .

That will yield you same answer @Harsh Shrivastava

- 2 years ago

- 2 years ago

For physics i suggest you to do HCV First that will help you to grasp concepts. Then move to fiitjee study material and Then Finally Archive . Doing this wont leave any concept behind . Then you can keep one reference book for harder problems of JEE Level (like I Prefer DC Pandey) . This will be more than enough and i guess it will be difficult to do all these simultaneously hence i did DC pandey after 2-3 chapters after i got sufficient time. i give more emphasis on packages and archives. And finally solve some problems of brilliant to challenge yourself.

@Harsh Shrivastava BTW I Did not got 23 in AIITS :p (as you told to look at questions of aniket)

- 2 years ago

Hello Prakhar. I wanted just one book for JEE Advanced Physics for difficult problems as we are almost through with the syllabus and need practice. Which according to you is the best and contains hard problems of every topic like here on brilliant.

- 11 months ago

Oh thanks for response.

- 2 years ago

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