I need a help in this problem. Please give a hint for question 17. The answer to this problem is 3:5.

Thanks!

I need a help in this problem. Please give a hint for question 17. The answer to this problem is 3:5.

Thanks!

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TopNewestBtw , which book ? @Harsh Shrivastava – Aniket Sanghi · 1 year, 1 month ago

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I have seen your name in recent solvers of many hard physics problems.

Please share some tips, thanks!

Also congrats for an amazing air 23 in aiits. – Harsh Shrivastava · 1 year, 1 month ago

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Btw can you please tell what sources you use for physics problems? Which books?(not for theory but

goodproblems.)Thanks.

@Aniket Sanghi – Harsh Shrivastava · 1 year, 1 month ago

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– Aniket Sanghi · 1 year, 1 month ago

Also , remember one thing - ' In Physics any question can be solved , if your concepts are perfect '. So 1st try to perfect your concepts . Try to solve the question more than asked , that is the question may be simple but their may be many things in it to think upon , using which good questions can be framed . :)Log in to reply

– Aniket Sanghi · 1 year, 1 month ago

I believe in cengage as 1st priority to gain confidence in basic , medium and some hard problems . Then I complete all q from it ( approx 200 to 300 q per chap) . Then I move to solve harder problems , I solve Irodov , Krotov , Brilliant , and I also try to make tougher questions on a topic which I didn't face in a book so as to check my knowledge and also to gain perfection! . :)Log in to reply

If you see geometry carefully , A0A1:A0A2:A0A3 = 3 : 5 : 6 .

How ? , see this - mark pts. Between A and A1 as B1 (above ) and B2 ( below) , similarly between A1 and A2 as B3 and B4 and between A2 and A3 as B5 and B6.

By geometry , angle A1A0B1= A2A1B3 = A3A2B5 = let x .

A0A1 = 2 × 3lcosx, A1A2 = 2 × 2lcosx, A2A3 = 2 × lcosx. And hence the ratio , A0A1:A0A2:A0A3 = 3 : 5 : 6 .

Differentiating both sides w.r.t t , we get v1 : v2 : v3 = 3 : 5 : 6 – Aniket Sanghi · 1 year, 1 month ago

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– Harsh Shrivastava · 1 year, 1 month ago

Thank you very much bro!Log in to reply

@Aniket Sanghi @Prakhar Bindal – Harsh Shrivastava · 1 year, 1 month ago

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In order to find lengths AOA1 , AOA2 I Used slightly different approach . I firstly used the fact that diagonals of rhombus bisect each other and then the property of parallogram sum of squares of sides = sum of squares of diagonals .

That will yield you same answer @Harsh Shrivastava – Prakhar Bindal · 1 year, 1 month ago

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@Prakhar Bindal – Harsh Shrivastava · 1 year, 1 month ago

Same questions to you that I have asked aniket, please reply thanksLog in to reply

@Harsh Shrivastava BTW I Did not got 23 in AIITS :p (as you told to look at questions of aniket) – Prakhar Bindal · 1 year, 1 month ago

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– Kushagra Sahni · 1 day, 6 hours ago

Hello Prakhar. I wanted just one book for JEE Advanced Physics for difficult problems as we are almost through with the syllabus and need practice. Which according to you is the best and contains hard problems of every topic like here on brilliant.Log in to reply

– Harsh Shrivastava · 1 year, 1 month ago

Oh thanks for response.Log in to reply