Hello :D I have a question, I have gotten home as a homework and I looking someone help who саn do my homework because don't quite understand how this works:

Break the following numbers into the product of their prime factors: 252, 882, 4000 and then:

Find the largest common divisor of 18.24 45, 54, 90

and last but not least:

Determine the least common multiple of

24, 56, 168

12, 18, 60

35, 49, 567

I know it's pretty much ... but I can not keep up on this topic: // well, thanks in advance :)

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3) LCM of 24,56,168 is \(168\)

LCM of 12,18,60 is \(180\)

LCM of 35,49,567 is \(10395\)

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2) \(18 = 2 \times 3 \times 3\)

\(24 = 2 \times 2 \times 2 \times 3\)

\(45 = 3 \times 3 \times 5\)

\(54 = 2 \times 3 \times 3 \times 3\)

\(90 = 2 \times 3 \times 3 \times 5\)

Out of all factors 3 is the only common factor. Therefore the highest common factor is 3.

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1) \(252 = 2^2 \times 3^2 \times 7\)

\(882 = 2 \times 3^2 \times 7^2\)

\(4000 = 2^5 \times 5^2\)

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