Two capacitors of capacities \(1 \mu F\) and \(C \mu F\) are connected in series and the combination is \(80 \mu C\), the energy stored in the capacitor of capacity C in \(\mu J\) is

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TopNewestIf it is \(80 \mu F\) then problem is incorrect since when 2 capacitor are connected in series, net capacitance is less than smallest of the individual capacitance. – Krishna Sharma · 2 years, 3 months ago

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– Tanishq Varshney · 2 years, 3 months ago

So it can be concluded the question is incorrect even if it is interpreted as the combination has \(80 \mu C\) charge.Log in to reply

– Krishna Sharma · 2 years, 3 months ago

I thought it was a typo I'll try taking it micro coulombsLog in to reply

80 microcoloumb is charge on capacitors , what is eq. Capacitance – Karan Siwach · 2 years, 3 months ago

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