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How to find this?

Note by Rajath Krishna R
4 years, 7 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

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$$\int_1^{3}[x]cos(\frac{\pi}{2}(x - [x]) dx \\ = \int_1^{2}[x]cos(\frac{\pi}{2}(x - [x]))dx + \int_2^{3}[x]cos(\frac{\pi}{2}(x - [x]))dx \\ = \int_1^{2} 1cos(\frac{\pi}{2}(x - 1) dx + \int_2^{3} 2cos(\frac{\pi}{2}(x - 2) dx \\ = \frac{1}{\frac{\pi}{2}} + 2 \frac{1}{\frac{\pi}{2}} \\ = \frac{6}{\pi}$$

- 4 years, 7 months ago