Hey Aryan! Nice question by the way..This question is related to Arithmetic Progression(A.P.)...although i am not sure if you know about them...you can see that every second term has a difference of 14...like the second term is -14 and the fourth term is 0, and similarly, the sixth term is +14...So the numbers at the even place form and A.P. with the first term (a) as -14 and the common difference (d) as +14...Since we are looking at the even places the number of term we need to find is not the 60th but the 30th term. So the number of term we need to find (n) is 30. Therefore, using the formula for finding the n'th term...

n'th term = a + (n-1) d

= -14 + (30-1) 14
= -14 + 29 x 14
= -14 + 406
= 392 should be your answer

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TopNewestHey Aryan! Nice question by the way..This question is related to Arithmetic Progression(A.P.)...although i am not sure if you know about them...you can see that every second term has a difference of 14...like the second term is -14 and the fourth term is 0, and similarly, the sixth term is +14...So the numbers at the even place form and A.P. with the first term (a) as -14 and the common difference (d) as +14...Since we are looking at the even places the number of term we need to find is not the 60th but the 30th term. So the number of term we need to find (n) is 30. Therefore, using the formula for finding the n'th term...

n'th term = a + (n-1) d

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I guess so. First I thought that its just repetition of terms by change of signs. I will try it out and let you know.

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