There are two given inequalities:-

A - \({ v }^{ 2 }{ sin }^{ 2 }\theta >360\)

B - \({ v }^{ 2 }sin(2\theta )>100\)

Solve A and B such that for a particular value of \(\theta \) between 0 to \(\pi /2\) the value of v is minimum.

There are two given inequalities:-

A - \({ v }^{ 2 }{ sin }^{ 2 }\theta >360\)

B - \({ v }^{ 2 }sin(2\theta )>100\)

Solve A and B such that for a particular value of \(\theta \) between 0 to \(\pi /2\) the value of v is minimum.

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TopNewestCan any one please solve this? – Tushar Gopalka · 2 years, 1 month ago

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Divide A by B so that v cancels

Now Solve for \(\theta\) – Krishna Sharma · 2 years, 1 month ago

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