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\[\large \lim_{n\to\infty} n \coth n = \, ?\]

Note by Soma Arjun 8 months, 3 weeks ago

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\[ \coth{x} = \dfrac{e^{2x}+1}{e^{2x}-1} \]

\[ \lim_{x \to \infty} \coth{x} = 1 \]

\[ \lim_{x \to \infty} x\coth{x} = +\infty \] – Sambhrant Sachan · 8 months, 2 weeks ago

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@Sambhrant Sachan – Thank you so much . I appreciate you for your response. – Soma Arjun · 8 months, 2 weeks ago

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TopNewest\[ \coth{x} = \dfrac{e^{2x}+1}{e^{2x}-1} \]

\[ \lim_{x \to \infty} \coth{x} = 1 \]

\[ \lim_{x \to \infty} x\coth{x} = +\infty \] – Sambhrant Sachan · 8 months, 2 weeks ago

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– Soma Arjun · 8 months, 2 weeks ago

Thank you so much . I appreciate you for your response.Log in to reply