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# How to solve this limit?

$\large \lim_{n\to\infty} n \coth n = \, ?$

Note by Soma Arjun
10 months, 3 weeks ago

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$\coth{x} = \dfrac{e^{2x}+1}{e^{2x}-1}$

$\lim_{x \to \infty} \coth{x} = 1$

$\lim_{x \to \infty} x\coth{x} = +\infty$

- 10 months, 3 weeks ago

Thank you so much . I appreciate you for your response.

- 10 months, 3 weeks ago