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How to solve this limit?

\[\large \lim_{n\to\infty} n \coth n = \, ?\]

Note by Soma Arjun
4 days, 9 hours ago

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\[ \coth{x} = \dfrac{e^{2x}+1}{e^{2x}-1} \]

\[ \lim_{x \to \infty} \coth{x} = 1 \]

\[ \lim_{x \to \infty} x\coth{x} = +\infty \] Sambhrant Sachan · 3 days, 1 hour ago

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@Sambhrant Sachan Thank you so much . I appreciate you for your response. Soma Arjun · 3 days ago

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