Can you approximate \( n \pi - \sqrt{ ( n \pi ) ^2 - 9 } \) as \(n\) gets large? Use Big-O notation if you are familiar with that.

Are you sure that there is an \( e^3 \) in there?

Also, please use distinct values for your indices. You cannot take the sum of the variable \(n\) , as it goes from 1 to \(n\).
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Calvin Lin
Staff
·
2 years, 8 months ago

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@Calvin Lin
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I am not familiar with that , I am sure that this is the question . Unable to solve that's why shared it and mentioned some brilliant members.

In a magazine - Mathematics today I saw it , Chapter - definite integration , section - Sandwich theorem
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U Z
·
2 years, 8 months ago

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Shivang Jindal Ronak Agarwal Pratik Shastri Sudeep Salgia @Rube
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U Z
·
2 years, 8 months ago

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TopNewestCan you approximate \( n \pi - \sqrt{ ( n \pi ) ^2 - 9 } \) as \(n\) gets large? Use Big-O notation if you are familiar with that.

Are you sure that there is an \( e^3 \) in there?

Also, please use distinct values for your indices. You cannot take the sum of the variable \(n\) , as it goes from 1 to \(n\). – Calvin Lin Staff · 2 years, 8 months ago

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In a magazine - Mathematics today I saw it , Chapter - definite integration , section - Sandwich theorem – U Z · 2 years, 8 months ago

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Shivang Jindal Ronak Agarwal Pratik Shastri Sudeep Salgia @Rube – U Z · 2 years, 8 months ago

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What is p? – Abhay Agnihotri · 2 years, 8 months ago

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– U Z · 2 years, 8 months ago

sorry its \(\pi\)Log in to reply