Given that \(s\) and \(t\) equals
and \(p\) and \(q\) such that
Manipulating a little bit, \(T\) should become
See how \(T\) and \(S\) have a \(\pm\) in them? When you subtract \(s\) from \(t\), why does that \(\pm\) disappear, and does it equal to the same value as when they have the \(\pm\) sign in them?
If you want to see this website, it is: Deriving the Cubic Formula
Comments
Sort by:
Top NewestYup, a simpler way to prove that cubic formula is to first depress the cubic polynomial. Cardano's method shows a good illustration of this. – Pi Han Goh · 7 months, 2 weeks ago
Log in to reply
Do you see the last 2 pictures? I was wondering what method allows you to get rid of that \(\pm\) sign. – Bloons Qoth · 7 months, 2 weeks ago
Log in to reply