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How you do cubic? \(\pm\)

Given that \(s\) and \(t\) equals

and \(p\) and \(q\) such that

Manipulating a little bit, \(T\) should become

See how \(T\) and \(S\) have a \(\pm\) in them? When you subtract \(s\) from \(t\), why does that \(\pm\) disappear, and does it equal to the same value as when they have the \(\pm\) sign in them?

If you want to see this website, it is: Deriving the Cubic Formula

Note by Bloons Qoth
7 months, 2 weeks ago

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Yup, a simpler way to prove that cubic formula is to first depress the cubic polynomial. Cardano's method shows a good illustration of this. Pi Han Goh · 7 months, 2 weeks ago

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@Pi Han Goh Do you see the last 2 pictures? I was wondering what method allows you to get rid of that \(\pm\) sign. Bloons Qoth · 7 months, 2 weeks ago

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