Given that \(s\) and \(t\) equals

and \(p\) and \(q\) such that

Manipulating a little bit, \(T\) should become

See how \(T\) and \(S\) have a \(\pm\) in them? When you subtract \(s\) from \(t\), why does that \(\pm\) disappear, and does it equal to the same value as when they have the \(\pm\) sign in them?

*If you want to see this website, it is: Deriving the Cubic Formula*

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## Comments

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TopNewestYup, a simpler way to prove that cubic formula is to first depress the cubic polynomial. Cardano's method shows a good illustration of this.

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Do you see the last 2 pictures? I was wondering what method allows you to get rid of that \(\pm\) sign.

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