Waste less time on Facebook — follow Brilliant.
×

http://math-utilities.com/ - A website for frequently used utilities(factorization, remainder, prime check, real roots of polynomials, etc. )

Hi Brilliant folks,

I made a website http://math-utilities.com/, for the sake of this community. Feel free to head over to that page, and make use of it. I love this problem solvers community and felt its my bit to help others along their journey.
Thanks a lot! Any cheers and blessings are much appreciated.

Note by Siva Bathula
3 weeks ago

No vote yet
1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

Nice Code.Well Done!!!!!!!!!!!!!!!!!!!!!!!!

Sumukh Bansal - 2 weeks, 3 days ago

Log in to reply

Thank you. Thumbs up :)

Siva Bathula - 2 weeks, 3 days ago

Log in to reply

How to find last three digits of 7^999 without using Euler's function or by using it also. Will it be true for all primes like 13^999 or any other. Please let me know it. And about this website, it is a good one.

Ayush Kumar - 6 days, 2 hours ago

Log in to reply

Good website

Rajyawardhan Singh - 2 weeks, 1 day ago

Log in to reply

Will you please send me ur email address. I have to send you some solutions.

Ayush Kumar - 6 days, 2 hours ago

Log in to reply

Nice website!

Munem Sahariar - 2 weeks, 2 days ago

Log in to reply

@Siva Bathula Good work!

Thanks for it.

Ankit Kumar Jain - 2 weeks, 2 days ago

Log in to reply

Neat website!

(25^27^29)mod1000 [works 99% of the time]

Why do you think that this function does not always work?

Polynomial equation solver(real roots only). Uses biection method.

What if there are multiple real roots between the "Start" and "End"?

Pi Han Goh - 2 weeks, 2 days ago

Log in to reply

The remainder finding algorithm fails in certain cases. I am not yet sure if it is closer to 100% but I have improved it to cut down some border cases. The polynomial eq. solver gives all real roots between Start and End. Thanks a lot for the neat comment! Looking forward for more positive feedback.

Siva Bathula - 2 weeks, 2 days ago

Log in to reply

Your "bisection method" section might be flawed.

I've submitted 1,3,3,1 for the coefficients, and the range between -10 and 10.

The answer spits out -1.007937, but it should be just -1 (with a multiplicity of 3).

Plus, you might want to add a function to find the multiplicity of the roots.


Your "Cubic equation solver" might be flawed as well.

I've submitted 1,3,3,1 for the coefficients as well, and it outputs: NaN for all x1, x2, x3.


Your GCD and LCM are flawed too.

If I submit "-2, -4" in GCD, it should spit out 2, not -2.

If I submit "-2, -1, -3" in LCM, it should spit out 6, not -6.

Pi Han Goh - 2 weeks, 2 days ago

Log in to reply

@Pi Han Goh Yeah, I was too fast to commit, without checking all the possibilities.

Siva Bathula - 2 weeks, 2 days ago

Log in to reply

How to get PDF of functional equations book by BJ Venkatachala

Ayush Kumar - 1 week, 1 day ago

Log in to reply

It's pdf is not available

Rajyawardhan Singh - 6 days, 17 hours ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...