Hi Brilliant folks,

I made a website http://math-utilities.com/, for the sake of this community. Feel free to head over to that page, and make use of it.
I love this problem solvers community and felt its my bit to help others along their journey.

Thanks a lot! Any cheers and blessings are much appreciated.

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Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

`*italics*`

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italics`**bold**`

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boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

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Remember to wrap math in`\(`

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to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

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TopNewestHow to find last three digits of 7^999 without using Euler's function or by using it also. Will it be true for all primes like 13^999 or any other. Please let me know it. And about this website, it is a good one.

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Great!

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How to get PDF of functional equations book by BJ Venkatachala

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It's pdf is not available

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Good website

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Will you please send me ur email address. I have to send you some solutions.

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Nice website!

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@Siva Bathula Good work!

Thanks for it.

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Neat website!

Why do you think that this function does not always work?

What if there are multiple real roots between the "Start" and "End"?

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The remainder finding algorithm fails in certain cases. I am not yet sure if it is closer to 100% but I have improved it to cut down some border cases. The polynomial eq. solver gives all real roots between Start and End. Thanks a lot for the neat comment! Looking forward for more positive feedback.

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Your "bisection method" section might be flawed.

I've submitted

`1,3,3,1`

for the coefficients, and the range between -10 and 10.The answer spits out -1.007937, but it should be just -1 (with a multiplicity of 3).

Plus, you might want to add a function to find the multiplicity of the roots.

Your "Cubic equation solver" might be flawed as well.

I've submitted

`1,3,3,1`

for the coefficients as well, and it outputs: NaN for all x1, x2, x3.Your GCD and LCM are flawed too.

If I submit "-2, -4" in GCD, it should spit out 2, not -2.

If I submit "-2, -1, -3" in LCM, it should spit out 6, not -6.

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Nice Code.Well Done!!!!!!!!!!!!!!!!!!!!!!!!

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Thank you. Thumbs up :)

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