I think there isn't enough information to be able to solve this problem. We need probability distribution function to know about the probability of getting 2 calls in following 2 minutes.
–
Lokesh Sharma
·
2 years, 9 months ago

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By Poisson distribution \( \lambda = 8 \) calls per two minutes.

So the answer on 1. is

\( P(X < 2) =0.003019\)

The answer on 2. is \( 4 \) (average number of calls in any minute is \( 4 \)).
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Bogdan Kejžar
·
2 years, 9 months ago

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TopNewestI think there isn't enough information to be able to solve this problem. We need probability distribution function to know about the probability of getting 2 calls in following 2 minutes. – Lokesh Sharma · 2 years, 9 months ago

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By Poisson distribution \( \lambda = 8 \) calls per two minutes.

So the answer on 1. is

\( P(X < 2) =0.003019\)

The answer on 2. is \( 4 \) (average number of calls in any minute is \( 4 \)). – Bogdan Kejžar · 2 years, 9 months ago

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thanks ! – Ahmed Hassaneen · 2 years, 9 months ago

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Ans 1)1/4 Ans 2) 4 – Aayush Mani · 2 years, 9 months ago

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– Jitesh Mittal · 2 years, 9 months ago

Can you explain your answer by providing a solutionLog in to reply

ANS :- 1) 3.94 and 2) 4 – Ajit Panada · 2 years, 9 months ago

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– Anmol Arora · 2 years, 9 months ago

How can probability be more than one?Log in to reply