You need new shoes but you do not have money.

And you borrow to 2 of your friends each 50 $.

When you want to buy shoes, shoes price was only 97$. you restore each 1$ to your friends and the remaining $ 1 you buy a drink.

so, the rest of your debt to your friends remaining 49$.

if 49 + 49 = 98 (because you have to restore 1$) so, if coupled with the money that you traded for a drink only 1$. mean 98 + 1 = 99. where 1$ is?

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TopNewestI am almost certain there is a break in the logic in the very last sentence. The logic just doesn't add up; one would be coupling money in two different states -that which is 'owed' and that which is 'spent'. So the last interrogative sentence(which really sounds like a paradox, but is really a misleading false statement) should really be- "... so, if coupled with the money traded for a drink which is 1$ this will mean 98$ - 1$ = 97$, so what is the problem?"

The question posed is a variation of (Eq:II) and therefore must be:- Amount owed - Money spent on the drink = Money spent on the shoes. Thus algebraic equilibrium holds and this means that there is no break in this logic. (For all purposes of this post - the drink was bottled water) – Judah Pereira · 1 year, 6 months ago

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