Waste less time on Facebook — follow Brilliant.

if the radius of the bubble is .7 mm , find depth at which the bubble remains in equillibrium , surface tension is 7×10^-2N/m and g is 10m/s^2

Pin-pout=2t/r but dont know how to calculate pin , any thoughts???

Note by Avinash Iyer
3 years, 8 months ago

No vote yet
1 vote


There are no comments in this discussion.


Problem Loading...

Note Loading...

Set Loading...