If f(x)=\(arcsin(\sin(\pi x))\).

Find

f(2.7)

f'(2.7)

\(\int^{2.5}_0 {f(x)} {dx}\)

If 1000 people are sitting around a circular table and each person makes a donation of the average of the two people sitting adjacent to him/her and it is known that one person made a contribution of 500 dollars, then find, if you can, the total amount donated and the maximum amount of money donated.

If \(p(x)=(x+a_1)(x+a_2)...(x+a_{10})\) is a polynomial such that \(\forall a_i \in R\) and all the 11 coefficients are positive, then answer true or false for the following questions:

p(x) has a global minimum.

\(a_i\) are all positive.

p'(x) has all negative real roots.

- p'(x) has all real roots.

## Comments

Sort by:

TopNewestThe second one was actually modified a little bit, but the answer is still the same.

Let A be the guy who donated 500 dollars. C must have donated 500+x and G must have donated 500-x, where x is any real number.With a little bit of simplification, you can see that D must have given 500+2x and F must have given 500-2x, and so on. The last guy, E, also gives 500 dollars. Because of symmetry, you can see that if you add it all up, you get 500*1000=500000.

Note that the maximum amount of money donated can never be found out because everyone could have given the same amount, i.e, x=0 is also a possible scenario. – Vishnu C · 2 years, 2 months ago

Log in to reply

@Brian Charlesworth , I could some help with the third one. – Vishnu C · 2 years, 2 months ago

Log in to reply

Okay, here's how you do the first one:

First draw the graph of the function. Although mathematically inaccurate, it's going to be a series of triangles with base on the x-axis.

2.7=2.5+0.2. When the arcsin function is applied, it is going to give you (0.5-0.2)

pi=0.3piAs the function has a slope = -PI at x=2.7.

The integral is pretty simple. It's the area under the curve. Height =PI/2 and base = 1/2 and there is one triangle like that because the positive and negative areas cancel out. And you get PI/8. – Vishnu C · 2 years, 2 months ago

Log in to reply