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# IMO 2016

Triangle BCF has a right angle at B let A be the point on line CF such that FA = FB and F lies between A and C . Point D is chosen such that DA = DC and AC is the bisector of ∠DAB . Point E is chosen such that EA = ED and AD of ∠EAC. Let M be the midpoint of CF . Let X be the point such that AMXE is a parallelogram (where AM || EX and AE || MX ) Prove that BD , FX and ME are concurrent lines .

Note by Rohit Camfar
3 weeks, 5 days ago

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