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Find x?

1+x=x

Note by Siddharth Singh 3 years, 3 months ago

Easy Math Editor

*italics*

_italics_

**bold**

__bold__

- bulleted- list

1. numbered2. list

paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)

> This is a quote

This is a quote

# I indented these lines # 4 spaces, and now they show # up as a code block. print "hello world"

2 \times 3

2^{34}

a_{i-1}

\frac{2}{3}

\sqrt{2}

\sum_{i=1}^3

\sin \theta

\boxed{123}

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No solution because if you cancel out the 'x's you'll get 1=0 which is simply not possible.

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I think it is indeterminate form since it will be in the form of \(\dfrac{1}{0}\) .

The answer is \( x \in C\) ,where C is the set of Complex numbers .

I don't get which complex number will satisfy the above equation.

But I think the above equation is satisfied as \(x\to\infty\).

Enter an Complex number in place of x , 1=0 . The constant=constant equality still holds .

I think this kind of equality is used in solving questions based on Inequalities .

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Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

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TopNewestNo solution because if you cancel out the 'x's you'll get 1=0 which is simply not possible.

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I think it is indeterminate form since it will be in the form of \(\dfrac{1}{0}\) .

Log in to reply

The answer is \( x \in C\) ,where

Cis the set of Complex numbers .Log in to reply

I don't get which complex number will satisfy the above equation.

But I think the above equation is satisfied as \(x\to\infty\).

Log in to reply

Enter an Complex number in place of

x, 1=0 . The constant=constant equality still holds .I think this kind of equality is used in solving questions based on Inequalities .

Log in to reply