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# Inequalities: Part 1

Prove that:

$$\displaystyle ab(a+b)+bc(b+c)+ac(a+c)\geq \sum_{cyclic}ab\sqrt{\frac{a}{b}}(b+c)(c+a)$$

where, $$\displaystyle \sum_{cyclic}ab\sqrt{\frac{a}{b}}(b+c)(c+a)=ab\sqrt{\frac{a}{b}}(b+c)(c+a)+bc\sqrt{\frac{b}{c}}(c+a)(a+b)+ca\sqrt{\frac{c}{a}}(a+b)(b+c)$$

So, prove that:

$$\displaystyle ab(a+b)+bc(b+c)+ac(a+c)\geq ab\sqrt{\frac{a}{b}}(b+c)(c+a)+bc\sqrt{\frac{b}{c}}(c+a)(a+b)+ca\sqrt{\frac{c}{a}}(a+b)(b+c)$$

Please post the complete solution with all the steps mentioned and the inequalities used. I'm facing problem to solve this inequality. Please help.

Note by Saurabh Mallik
2 months, 3 weeks ago