# Infinite cubic grid of resisrors

Can we find net resistance between the body diagonal points of a infinite cubic lattice ?

The objective is to find net resistance between A & B of the given cube which is part of infinite grid. Let the resistance between any two adjacent vertices is R

Note by Pranjal Prashant
5 years, 8 months ago

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see 2nd answer to the question in the link https://physics.stackexchange.com/questions/2072/on-this-infinite-grid-of-resistors-whats-the-equivalent-resistance It's for n dimensional grid

- 11 months, 1 week ago

It must be R/3

- 5 years, 1 month ago

- 5 years ago

Solution ?

- 5 years, 1 month ago

Yes, I know about 2 d version for resistors and fourier series for getting across square diagonal 2r/pi.[you know that Ishan :D ] But this is quite different fom those, much more difficult in getting the approach. You should share this so that someone reaches at the final ansWeR.

- 5 years, 8 months ago

Oh my.

Staff - 5 years, 8 months ago

Staff - 5 years, 8 months ago

A simpler version would be two find the equivalent resistance between two diagonally opposite points in an infinite grid of resistors, which is still quite difficult. See the page I have linked Infinite grid of resistors

- 5 years, 8 months ago

Total resistance (across points A and B) = ( 5/6 ) * R
I can't post a picture of my solution here

- 5 years, 8 months ago

Incorrect, This answer holds if there was a single cube of resistances rather than an infinite one.

- 5 years, 8 months ago

but infinite series of resistors just push the "single cube value" to an exact number so my idea is that effective resistance is near (5/6)R (like 0.85R or 0.9R max but not less than (5/6)R). Please notify me if there is a mistake in my assumption.

- 5 years, 8 months ago

Now what significance pushing values is of, the question is not an mcq, I want to know how it can be done, and I am sure that it is solvable. {although answer would not be beautiful perhaps}.

- 5 years, 8 months ago

got it but I dont know how to solve the way you told and yes the answer sure will be weird

- 5 years, 8 months ago

NO, IT IS NOT SO. In the fourier series , steps of integration are nasty, but answer is simply 2r/ $\pi$

- 5 years, 8 months ago

thanks for the info I will surely try to get the steps for your answer.

- 5 years, 8 months ago

I could not understand "push the single cube value to an exact number". Also think of 2-D grid of infinite resistors in which we have to find the equivalent resistance between adjacent points which everyone knows to be R/2. What will be your argument in this one? Just because other resistances are present does not mean that the net would be greater than 5R/6 because resistances in parallel decrease the value

- 5 years, 8 months ago

Yes it is haha, I considered only a 'cube'.

- 5 years, 8 months ago