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Consider two particles a and b both being at ends of a line of length l . B is moving with acceleration 'b' while A moves with acceleration 'a' . A moves in such a way that it continuously follows B. find the time after which they meet.

Note by Dheeraj Agarwal 3 years ago

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Is the answer \(T=\sqrt {\dfrac{2l}{(a-b)}}\)?

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Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

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TopNewestIs the answer \(T=\sqrt {\dfrac{2l}{(a-b)}}\)?

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