This is a logic puzzle that I really enjoy, but it doesn't translate well to the "input your answer" format. That aside, I thought people on Brilliant might enjoy it too.

The logic mastermind has taken 100 mathematicians hostage. The mathematicians are told that they will each be given a hat out of 100 possible colors (the mathematicians are told the possible colors in advance). The mathematicians must then **simultaneously** guess their own hat colors. (Note that they all must guess; **no one may abstain.**)

The mathematicians are able to see the other 99 hats but not their own. Moreover, they are not allowed to communicate any information to the other mathematicians (e.g. by physical movement or change in tone) on pain of death - they must only guess.

The mathematicians will be set free if ** EXACTLY ONE** mathematician guesses correctly. Unfortunately, they are told that their hat colors may not necessarily be distinct - for example, while there are 100 possible hat colors, they might all be given yellow hats.

The mathematicians are allowed to devise a strategy before they don their hats and guess. Can they succeed and win their freedom? If so, what is their strategy?

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## Comments

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TopNewestAnd there are several other hat problems like this and this and this. That's amazing! Thanks Maggie!

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I have a solution for this problem. But I don't see how the mathematicians can do it without communicating. The solution involves assigning numbers, which involves communication. I suppose that means I don't have a solution.

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The mathematicians are allowed to devise a strategy before putting on hats, so they may communicate at that time. They can't communicate once the hats are on.

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Okay! Thanks for posting this problem, it was interesting

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There are 100 caps, that might be distinctively colored or similarly. Since there is no observed pattern of slaying the riddle, nor is there any mention of the colours, its practically impossible to find the right colour of the hat unless guesses are allowed.

Oppositions to my answer are most welcome! :)

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Well they are each guessing - no one certainly knows their own hat color, but they do know that exactly one person will guess correctly. There is a solution :)

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