# Interesting Probability Problem

Suppose you've a rectangle of $$1 \times 2$$ unit squares area. If you start swiping a pointer over its perimeter through a knob switch, by turning it. What's the probability that when you stop(at random), you'd stop at any of the corner points of that rectangle? NOTE: I don't have the answer.

5 years, 8 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

This is a great example of an interesting problem contributed by students, that is badly phrased and hence is rejected. The author has an opinion of what must happen, but fails to convey the proper meaning. The knob switch does something in his mind, but he fails to elucidate what that means. As such, there could be several interpretations of it.

Are we only restricted to the corners? It is not mentioned, and Bob's interpretation of the problem is valid.

How does the $$1 \times 2$$ squares come into play? It is not mentioned, and Aditya's interpretation of 'randomly stop on vertices' is valid.

Staff - 5 years, 8 months ago

The answer is zero. The probability you land exactly on a point is zero, since there are an infinite amount of points in a line. Either that, or you've explained the problem incorrectly.

- 5 years, 8 months ago

What if he meant that the knob switch lets you stop only on lattice points on the perimiter? Probability now is $$\frac{2}{3}$$.

- 5 years, 8 months ago

The issue with your interpretation is that the author explicitly says "Doesn't sound correct!" (see below).

I look at the further comment, and I seem to think that his objection is not valid, but I do not know for certain till it is clear what the knob does.

This is why he needs to explain clearly what the knob actually does.

Staff - 5 years, 8 months ago

Knob is actually a device that helps us move pointer over the rectangle. That's it!

- 5 years, 8 months ago

i disagree, the probability tends to zero though, and hey, there's 4 vertices.

- 5 years, 3 months ago

I think it should be it should be 4/6 or 2/3.

- 5 years, 8 months ago

Doesn't sound correct!

- 5 years, 8 months ago

That means I have misinterpreted the working of the knob switch, if you could explain that.

- 5 years, 8 months ago

Knob is not affecting the your answer. The point is that when you say 4/6, you're taking 6 as lengths and 4 as points. That ratio can't be said equal to probability. What's your view?

- 5 years, 8 months ago

1/4

- 5 years, 8 months ago

Explanation?

- 5 years, 8 months ago

i think an illustration of whatever you mean by "swiping a pointer over its perimeter through a knob switch" would help. No clue what this means. I'm imagining one of those toys where you draw with knobs

- 5 years, 3 months ago