I want to get clarified with numbers ending with 9. I have considered 2 digit numbers and not extending it further as of now.

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If we have 2 digit numbers of the form 10a + b and ending with 9,
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Then, \(ab + a+b= 10a+b \).

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## Comments

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TopNewestI assume that \(a\) is a single digit positive integer and \(b\) is a non-negative single digit integer, then obviously \(b=9\) and so your equation holds true.

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Yes..I considered only 2 digit numbers. I need to know how it works!

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After you know that \(b=9\), what happens when you substitute \(b=9\) into the equation \(ab + a +b = 10a + b\)?

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For instance a =1, the equation becomes 1*9 + 1 + 9 = 19 = 10(1) + 9 = 19.

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I asked you to substitute \(b=9\) alone only, nothing else. What happens to the equation \(ab+ab+b=10a+b\) after you substitute \(b=9\)?

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application of divisibility rules.

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