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# Interval

X^2<5

Note by Paras Queen
4 years, 2 months ago

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$$x^2 < 5 \rightarrow x^2 - 5 < 0$$

$$\Delta = 0^2 -4 \cdot -5 \cdot 1 = 20$$

$$x= \frac{0 \pm \sqrt20}{2}$$

$$x_1 = \frac{2\sqrt5}{2} = \sqrt5$$

$$x_2 = \frac{-2\sqrt5}{2} = -\sqrt5$$

($$x \in\mathbb{R} / -\sqrt5< x < \sqrt5$$)

- 4 years, 2 months ago

x<(5)^1/2

- 4 years, 2 months ago

Not necessarily. There's more to it.

- 4 years, 2 months ago