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X^2<5

Note by Paras Queen
3 years, 4 months ago

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\(x^2 < 5 \rightarrow x^2 - 5 < 0\)

\(\Delta = 0^2 -4 \cdot -5 \cdot 1 = 20\)

\(x= \frac{0 \pm \sqrt20}{2} \)

\(x_1 = \frac{2\sqrt5}{2} = \sqrt5\)

\(x_2 = \frac{-2\sqrt5}{2} = -\sqrt5\)

(\(x \in\mathbb{R} / -\sqrt5< x < \sqrt5\)) Gabriel Merces · 3 years, 4 months ago

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x<(5)^1/2 Shaheed Vh · 3 years, 4 months ago

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@Shaheed Vh Not necessarily. There's more to it. Daniel Leong · 3 years, 4 months ago

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