To start a new year with the love for math and science, I made a funny solving of a "Today's" problem. Disliking it counts as a like to me :P . For the introduction of the new year:

The following steps explain the solving process of the problem (1 Jan 2020) [it is about the no. 2020 we ae doing math with]:

We want to express 2020 in the form of $a^{2} -b^{2}$ :

- $2020 = a^{2} -b^{2} = (a+b) \times (a-b)$
- Since these are powers, we can use the $Yeet.theorem$ to yeet over the exponent: $2020 = 2 \times a -2 \times b$
- $1010 = (a - b)$
- We repalce $(a-b)$ with 1010 at eq.1 which we get:
- $2020 = (a+b) \times (1010)$
- $2 = (a+b)$ divide both sides by 1010

We have the given system to solve: $\begin{cases} 2 = (a+b) \\ 1010 = (a - b) \end{cases}\$

- $1012 = (a + b) + (a - b)$
- $1012 = 2 \times a$
- $506 = a$

Finding $b$:

- $1010 = (506 - b)$
- $b = - 504$

But we cannot have negative numbers so $b = 504$.

We have solution that $\boxed{2020 = 506^{2} -504^{2}}$

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## Comments

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TopNewestThis is Funny!

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"Yeet Theorem" I'm dying

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I don't get the Yeet Theorem well yeet.

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It is a joke; a meme, that represents a 'proof' of a theorem:

read this to understand how it works

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It was just a pun. But thank you anyway.

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Looks like this year yeeted us as well. Yeet.

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Good one!

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It's even better that it actually works! Good joke.

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This is misuse of the Yeet Theorem. The Yeet theorem states that you can yeet the exponents to the end of the equation.

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Just saying, this is a joke, I'm not trying to be mean in any way.

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