Introduction to the new decade 2020 !

To start a new year with the love for math and science, I made a funny solving of a "Today's" problem. Disliking it counts as a like to me :P . For the introduction of the new year:

You can skip this note if you are not into jokes.

The following steps explain the solving process of the problem (1 Jan 2020) [it is about the no. 2020 we ae doing math with]:

We want to express 2020 in the form of a2b2 a^{2} -b^{2} :

  • 2020=a2b2=(a+b)×(ab)2020 = a^{2} -b^{2} = (a+b) \times (a-b)
  • Since these are powers, we can use the Yeet.theoremYeet.theorem to yeet over the exponent: 2020=2×a2×b2020 = 2 \times a -2 \times b
  • 1010=(ab)1010 = (a - b)
  • We repalce (ab)(a-b) with 1010 at eq.1 which we get:
  • 2020=(a+b)×(1010)2020 = (a+b) \times (1010)
  • 2=(a+b)2 = (a+b) divide both sides by 1010

We have the given system to solve: {2=(a+b)1010=(ab)  \begin{cases} 2 = (a+b) \\ 1010 = (a - b) \end{cases}\

  • 1012=(a+b)+(ab)1012 = (a + b) + (a - b)
  • 1012=2×a1012 = 2 \times a
  • 506=a506 = a

Finding bb:

  • 1010=(506b)1010 = (506 - b)
  • b=504b = - 504

But we cannot have negative numbers so b=504b = 504.

We have solution that 2020=50625042 \boxed{2020 = 506^{2} -504^{2}}

Note by Nickolas Крај
3 weeks, 3 days ago

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This is Funny!

Shravan Balaji - 3 weeks, 3 days ago

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"Yeet Theorem" I'm dying

Mountain Cheng - 3 weeks, 2 days ago

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I don't get the Yeet Theorem well yeet.

Félix Pérez Haoñie - 2 weeks, 6 days ago

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It is a joke; a meme, that represents a 'proof' of a theorem:

read this to understand how it works

Nickolas Крај - 2 weeks, 5 days ago

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It was just a pun. But thank you anyway.

Félix Pérez Haoñie - 2 weeks, 5 days ago

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Good one!

Carlos Manuel Lima Ribeiro - 3 weeks, 2 days ago

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It's even better that it actually works! Good joke.

Essey Andemariam - 3 weeks, 2 days ago

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This is misuse of the Yeet Theorem. The Yeet theorem states that you can yeet the exponents to the end of the equation.

Patrick Chen - 3 weeks, 1 day ago

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