Say you have \(f(x) \) and \(g(x)\) and \(g(x) = f^{-1}(x) \).

I observed that these two curves need not intersect, for example with \(f(x) = e^x\) and \(g(x) = \ln x \) never intersecting each other.

I also observed that a function can either have one, two, or three intersections with its inverse, but I was unable to find a function which has more than 3 intersection points with its inverse.

How would I prove or disprove the hypothesis that an elementary function and its intersection can only have up to 3 intersection points? Any counterexamples are appreciated!

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TopNewestConsider \(f(x) = x\).

Note that \(g(x) = f^{-1}(x) = x = f(x)\).

So, there are infinitely many intersections! – Deeparaj Bhat · 2 months ago

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Good solution. I am aware of the infinite intersections solution, but does anyone have any functions which have 4 or more intersections with their inverse (but not an infinite number of intersections)? – Oli Hohman · 1 month, 4 weeks ago

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Over the interval \(X\) there are finitely many intersections. The exact number depends on \(X\) itself. But you can have

anyfinite number of intersections. – Deeparaj Bhat · 1 month, 4 weeks agoLog in to reply

– Ian Limarta · 1 month, 3 weeks ago

Nice solutionLog in to reply