We know that for bijections, the graph of the function and its inverse are mirror images about the straight line x=y. hence, the always intersect on the line. is it possible to have a function for which the graph of the function and its inverse intersect outside the line x=y?

## Comments

Sort by:

TopNewestApperently any function which is also symmetric about x+y=0 satisfies the above conditions. Odd and one-one functions are some examples. – Abhishek Chakraborty · 2 years, 5 months ago

Log in to reply