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Invertible Functions with points of intersection outside x=y

We know that for bijections, the graph of the function and its inverse are mirror images about the straight line x=y. hence, the always intersect on the line. is it possible to have a function for which the graph of the function and its inverse intersect outside the line x=y?

Note by Abhishek Chakraborty
3 years ago

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Apperently any function which is also symmetric about x+y=0 satisfies the above conditions. Odd and one-one functions are some examples. Abhishek Chakraborty · 3 years ago

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