Why don't we add a constant of integration when integrating the second function while applying integration by parts? I'm searching for a perfectly logical answer

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TopNewestWhat is "the second function"? On \(\int u \, dv = uv - \int v \, du\), is the second function \(v\) or \(v \, du\)? – Ivan Koswara · 2 years ago

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– Sanchit Aggarwal · 2 years ago

The second function is 'dv', the function whose integral is 'v'Log in to reply

It will not affect the final answer. You can try it out yourself. The extra part, if you think there will be any, will get cancelled out at the end. – Sanchit Aggarwal · 2 years ago

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P.S. You have to integrate g(x) twice while applying by parts – Mayank Singh · 2 years ago

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P.s. refer to the derivation of the formula once – Sanchit Aggarwal · 2 years ago

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Thanks for asking this question, I had the same one in my mind! – Swapnil Das · 2 years ago

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– Mayank Singh · 2 years ago

Well I've reasoned something out... I'm waiting for some other repliesLog in to reply

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– Mayank Singh · 2 years ago

Just last yearLog in to reply