*No number is equal to any other no. except itself*
Stupid statement, isn't it??
Well, you might think that I declare it as stupid, and it is accepted worldwide.
But here…
Take a rational **x** and its negative,i.e., **-x**.
Square them, and they become**x^{2}**.
Now, They are equal.
Hence, taking square root on both sides, we get:
**X=-X**
Hence, disproved

## Comments

Sort by:

TopNewestu should go a bit deeper inside ur proof .....for a correct mathematical proof i think counts in it all the possible perspstives .....:-) – Tanmay Goyal · 2 years, 5 months ago

Log in to reply

– Vikram Venkat · 2 years, 4 months ago

Well, the proof is never the basis. I am waiting for a counter-statementLog in to reply

Let's oversimplify it ,

x^2=x^2 1st condition ,

x

x=xx2nd condition,

(-x) *(-x) = x * x

Now , you divide the whole equation by x, you see

x=x , you can only remove x from the equation not ( -1)*(-1)

That's why I said you should consider all possible perspectives ..!! – Tanmay Goyal · 2 years, 4 months ago

Log in to reply

There is no such number where its predecessor or its successor is the negative value of itself, just looking at the number 1, it has a predecessor of 0, and a successor of 2, neither equaling -1. – Brice Kessler · 2 years, 7 months ago

Log in to reply

– Vikram Venkat · 2 years, 7 months ago

Have a good look at it bro!!!Log in to reply

– Megh Choksi · 2 years, 6 months ago

be careful with squares and square roots , think once again for a whileLog in to reply

@megh choksi ??? – Vikram Venkat · 2 years, 5 months ago

What happenedLog in to reply