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Irrational Math…

No number is equal to any other no. except itself Stupid statement, isn't it?? Well, you might think that I declare it as stupid, and it is accepted worldwide. But here… Take a rational x and its negative,i.e., -x. Square them, and they becomex^{2}. Now, They are equal. Hence, taking square root on both sides, we get: X=-X Hence, disproved

Note by Vikram Venkat
2 years, 3 months ago

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u should go a bit deeper inside ur proof .....for a correct mathematical proof i think counts in it all the possible perspstives .....:-) · 2 years, 1 month ago

Well, the proof is never the basis. I am waiting for a counter-statement · 2 years ago

Just look here my friend

Let's oversimplify it ,

x^2=x^2 1st condition ,

xx=xx

2nd condition,

(-x) *(-x) = x * x

Now , you divide the whole equation by x, you see

x=x , you can only remove x from the equation not ( -1)*(-1)

That's why I said you should consider all possible perspectives ..!! · 2 years ago

There is no such number where its predecessor or its successor is the negative value of itself, just looking at the number 1, it has a predecessor of 0, and a successor of 2, neither equaling -1. · 2 years, 3 months ago

Have a good look at it bro!!! · 2 years, 3 months ago

be careful with squares and square roots , think once again for a while · 2 years, 2 months ago