*No number is equal to any other no. except itself*
Stupid statement, isn't it??
Well, you might think that I declare it as stupid, and it is accepted worldwide.
But here…
Take a rational **x** and its negative,i.e., **-x**.
Square them, and they become**x^{2}**.
Now, They are equal.
Hence, taking square root on both sides, we get:
**X=-X**
Hence, disproved

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## Comments

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TopNewestu should go a bit deeper inside ur proof .....for a correct mathematical proof i think counts in it all the possible perspstives .....:-)

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Well, the proof is never the basis. I am waiting for a counter-statement

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Just look here my friend

Let's oversimplify it ,

x^2=x^2 1st condition ,

x

x=xx2nd condition,

(-x) *(-x) = x * x

Now , you divide the whole equation by x, you see

x=x , you can only remove x from the equation not ( -1)*(-1)

That's why I said you should consider all possible perspectives ..!!

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There is no such number where its predecessor or its successor is the negative value of itself, just looking at the number 1, it has a predecessor of 0, and a successor of 2, neither equaling -1.

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Have a good look at it bro!!!

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be careful with squares and square roots , think once again for a while

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@megh choksi ???

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