*No number is equal to any other no. except itself*
Stupid statement, isn't it??
Well, you might think that I declare it as stupid, and it is accepted worldwide.
But here…
Take a rational **x** and its negative,i.e., **-x**.
Square them, and they become**x^{2}**.
Now, They are equal.
Hence, taking square root on both sides, we get:
**X=-X**
Hence, disproved

## Comments

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TopNewestu should go a bit deeper inside ur proof .....for a correct mathematical proof i think counts in it all the possible perspstives .....:-) – Tanmay Goyal · 2 years, 1 month ago

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– Vikram Venkat · 2 years ago

Well, the proof is never the basis. I am waiting for a counter-statementLog in to reply

Let's oversimplify it ,

x^2=x^2 1st condition ,

x

x=xx2nd condition,

(-x) *(-x) = x * x

Now , you divide the whole equation by x, you see

x=x , you can only remove x from the equation not ( -1)*(-1)

That's why I said you should consider all possible perspectives ..!! – Tanmay Goyal · 2 years ago

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There is no such number where its predecessor or its successor is the negative value of itself, just looking at the number 1, it has a predecessor of 0, and a successor of 2, neither equaling -1. – Brice Kessler · 2 years, 3 months ago

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– Vikram Venkat · 2 years, 3 months ago

Have a good look at it bro!!!Log in to reply

– Megh Choksi · 2 years, 2 months ago

be careful with squares and square roots , think once again for a whileLog in to reply

@megh choksi ??? – Vikram Venkat · 2 years, 1 month ago

What happenedLog in to reply