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TopNewestexact zero raise to the power exact zero is NOT DEFINED. – Ashutosh Mittal · 4 years, 3 months ago

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Read this funny yet informative article http://www.askamathematician.com/2010/12/q-what-does-00-zero-raised-to-the-zeroth-power-equal-why-do-mathematicians-and-high-school-teachers-disagree/ – Saurabh Dubey · 4 years, 3 months ago

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Watch this video – Micah Wood · 4 years, 3 months ago

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http://www.wolframalpha.com/input/?i=lim+x+is+approaching+to+0+x%5Ex – Tan Wei Sheng · 4 years, 3 months ago

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In calculus and other branches of mathematical analysis, an indeterminate form is an algebraic expression obtained in the context of limits. Limits involving algebraic operations are often performed by replacing subexpressions by their limits; if the expression obtained after this substitution does not give enough information to determine the original limit, it is known as an indeterminate form. The indeterminate forms include 0^0, 0/0, 1^∞, ∞−∞,∞/∞, 0 × ∞, and ∞/0.........so it's also a indeterminate form you have given.... – Raja Metronetizen · 4 years, 3 months ago

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0^0 = 0^(m-m) = 0^(m) . 0^(-m) .... now as, 0^(-m) = 1 / 0 which is undefined... so 0^0 = undefined .....well first I tried to prove it like this but then I found that it wasn't a good proof as it had contradictions . :( – Zubayet Zico · 4 years, 3 months ago

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it is indeterminate form in chapter limits.... – Riya Gupta · 4 years, 3 months ago

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– Aditya Parson · 4 years, 3 months ago

but mathematicians prove through limits that it it comes to 1?Log in to reply

– Riya Gupta · 4 years, 3 months ago

ok......can u xplain me how?Log in to reply

– Aditya Parson · 4 years, 3 months ago

read the article posted by Saurabh.Log in to reply

– Riya Gupta · 4 years, 3 months ago

ok thanks....i'll do that...Log in to reply

– Djordje Marjanovic · 4 years, 3 months ago

limits tell us that n/0 = inf but we know that n/0 is undefinedLog in to reply

well someone can give me the clear proof of any number raised to 0 is 1. – Diksha Verma · 4 years, 3 months ago

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yes we can prove it by log theorem? take log and calculate. – Attain k Gupta · 4 years, 3 months ago

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0^0=0/0-------------not defined – Sreehari Vp · 4 years, 3 months ago

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look at this.

4^2 = 16

4^1 = 4

4^0 = 1

why 4^0 = 1?

easy to proof. imagine that the exponent is absolutely like an element of carbon molecule. exponent is like a box that contain something, copy the box and paste then imagine that they will combine and has more energy, it will be two thing that are same like x*x in mathematic.

how about x^0?

so easy. it means that there are no element, like an empty box. because the box still present in universe, it mean there must be a symbol to represent it, that is the 1 or one. – Yulianto Indra Setiawan · 4 years, 3 months ago

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If 0^0=1 what's the proof and if 0^0= undefined what's the proof ??? – Zubayet Zico · 4 years, 3 months ago

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really nice question....... i think so it is undefined. – Diksha Verma · 4 years, 3 months ago

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– Aditya Parson · 4 years, 3 months ago

I agree with that. You can easily prove that it is an indeterminate form in mathematics,Log in to reply

– Diksha Verma · 4 years, 3 months ago

in laws of exponent they never mention that base a is not equal to 0Log in to reply

undefined. bt nt equal 2 1. – Shubham Malik · 4 years, 3 months ago

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The way I was taught, even though 0^0 is indeterminate, mathematicians will consider it to be 1. – Kenneth Chan · 4 years, 3 months ago

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– Arushit Mudgal · 4 years, 3 months ago

considering is different thing...sometimes in physics also we consider that 1/0 = infinity...but that is wrong.. 0^0 is undefinedLog in to reply

it should be zero.. – Diksha Verma · 4 years, 3 months ago

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– Aditya Parson · 4 years, 3 months ago

But many take it to be 1.Log in to reply

https://www.google.com/search?q=0^0 – Kenneth Chan · 4 years, 3 months ago

LIke google!Log in to reply

– Aditya Parson · 4 years, 3 months ago

Yes.Log in to reply

– Diksha Verma · 4 years, 3 months ago

only google calculator is showing 1! but other scientific calculators finds math error.Log in to reply

– Aditya Parson · 4 years, 3 months ago

I know that.Log in to reply

– Jatin Yadav · 4 years, 3 months ago

0^0 is neither 1 nor indeterminate, it is undefined... there is a difference between indeterminate and undefined. e.g. app.0/app.0 is indeterminate where as 0/0 is undefined similarly, 0^0 is undefined as 0^0 = e^(0log0) where log 0 is undefined, but (app. 0)^app.0 is indeterminate whose value is 1...if both functions which are approaching 0 used in (app0)^app0 are the same. if both functions are x. lim (x app0) x^x can be found by equating it to e^xlogx where if xapp. 0 xlogx approaches 0[this can be found by using LH rule] and hence x^x approaches 1(as e^0 = 1)Log in to reply

– Arushit Mudgal · 4 years, 3 months ago

Just a considerationLog in to reply