I prefer not to approach this question with AM-GM Inequality. Let \(y = x(x+10)\), we can write it into the form of \(y = (x+5)^2-25\). Here, the value \(x\) such that \(y\) is a minimum is \(x = -5\) and \(y = -25\). The two integers is then -5 and 5.
–
Kay Xspre
·
1 year, 6 months ago

## Comments

Sort by:

TopNewestI prefer not to approach this question with AM-GM Inequality. Let \(y = x(x+10)\), we can write it into the form of \(y = (x+5)^2-25\). Here, the value \(x\) such that \(y\) is a minimum is \(x = -5\) and \(y = -25\). The two integers is then -5 and 5. – Kay Xspre · 1 year, 6 months ago

Log in to reply