Is there any relation between both the given facts or this is coincidence :
sum of \(n\) natural numbers i.e. \(\frac { n(n+1) }{ 2 } \) and \({n+1 \choose 2}\)

Imagine the first one in a line of (n+1) persons saying "Hello" to all the n, second saying to remaining (n-1), third to rest of (n-2) and so on till the last but one says "Hello' to the last one. Total number of "Hello' is a combination term, 2 out of (n+1) as each and every pair said "Hello", which is also the sum of first n natural numbers.

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## Comments

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TopNewestYes There is relation between both If n(n+1)/2n When we have to find mean Then its equal to n+1/2

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please explain some more

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hey @Finn Hulse please answer it !!

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Okay.

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You answered it.

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Quote: 'hey @Finn Hulse please answer it !!'

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If you factor \(n+1\) choose \(2\) you get \(\dfrac{n(n+1)}{2!}\).

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oh! according to my knowledge \(2!\)\(=\)\(2\) so what is the relation between the two

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Imagine the first one in a line of (n+1) persons saying "Hello" to all the n, second saying to remaining (n-1), third to rest of (n-2) and so on till the last but one says "Hello' to the last one. Total number of "Hello' is a combination term, 2 out of (n+1) as each and every pair said "Hello", which is also the sum of first n natural numbers.

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