Yes... If a body moves on a circular path with a uniform speed then due to the continuous change in the direction of the body, the acceleration is variable.

yes...
When a charged particle enters a magnetic field perpendicular to it
then it experiences a force q[\(v\times b\)] which is always perpendicular to the velocity
and hence the charged particle follows a circular motion at a \( constant speed \) but at a varying velocity

In general whenever there is a force which is always perpendicular to the velocity vector then its component
along the velocity will be zero and the speed of the particle remains constant even if it is experiencing
Non Zero acceleration

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestYes... If a body moves on a circular path with a uniform speed then due to the continuous change in the direction of the body, the acceleration is variable.

Log in to reply

Pls Join iit jee preparation club at google groups.

Log in to reply

yes... When a charged particle enters a magnetic field perpendicular to it then it experiences a force q[\(v\times b\)] which is always perpendicular to the velocity and hence the charged particle follows a circular motion at a \( constant speed \) but at a varying velocity

In general whenever there is a force which is always perpendicular to the velocity vector then its component along the velocity will be zero and the speed of the particle remains constant even if it is experiencing Non Zero acceleration

Log in to reply

Thank you Ritesh.

Log in to reply

Ritesh you also pls join iit jee preparation club at google groups.

Log in to reply