Look up "Herschfeld's Convergence Theorem". It states that for real terms \({ { x }_{ n } }\ge 0\) and real powers \(1>p>0\) if and only if

\(\displaystyle{ { x }_{ n } }^{ { p }^{ n } }\)

is bounded, then the following converges

\({ x }_{ 0 }+{ \left( { x }_{ 1 }+{ \left( { x }_{ 2 }+{ \left( ...+{ \left( { x }_{ n } \right) }^{ p } \right) }^{ p } \right) }^{ p } \right) }^{ p }\)

as \(n\rightarrow \infty \)

Here, \(p=\frac { 1 }{ 2 } \), so it's easy to see how the condition is met.

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TopNewestThis is the "nested radical constant", also known as Vijayaraghavan's constant, which is \(1.75793275...\)

There is no exact expression for this constant.

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Sir, how do we find out whether a sum like this converges or not? Thanks.

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Look up "Herschfeld's Convergence Theorem". It states that for real terms \({ { x }_{ n } }\ge 0\) and real powers \(1>p>0\) if and only if

\(\displaystyle{ { x }_{ n } }^{ { p }^{ n } }\)

is bounded, then the following converges

\({ x }_{ 0 }+{ \left( { x }_{ 1 }+{ \left( { x }_{ 2 }+{ \left( ...+{ \left( { x }_{ n } \right) }^{ p } \right) }^{ p } \right) }^{ p } \right) }^{ p }\)

as \(n\rightarrow \infty \)

Here, \(p=\frac { 1 }{ 2 } \), so it's easy to see how the condition is met.

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Comment deleted Aug 28, 2015

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