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I have a problem with an isosceles triangle ABC , a=b , angle(A) = 15 degrees , the perimeter of the triangle = 25 CM , I need to find the area of the circumcircle of the triangle ABC.

Note by Joe Ayman 4 years, 9 months ago

Easy Math Editor

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2 \times 3

2^{34}

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R=25/(rt6-rt2+2), rtx= square root of x. then apply area= (pi)R^2.

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Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

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TopNewestR=25/(rt6-rt2+2), rtx= square root of x. then apply area= (pi)R^2.

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